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PLEASE HELP I NEED THE ANSWER BY 3PM EST ON 3/3/21
How do you find the time an object is at a certain height algebraically? For example, given the function h(t) = -16t2 +32t represents the height of a ball thrown from ground level. How do you find the time when the ball is 10 feet above the ground? Explain in your own words.

Sagot :

Sqdancefanidn

9514 1404 393

Explanation:

To find the time, substitute the height for h(t), then solve the quadratic equation for t.

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To solve the equation, you subtract the height from both sides, then use the quadratic formula. In generic terms, this looks like ...

  -16t^2 +32t -h = 0

  t = (-32±√(32^2 -4(-16)(-h)))/(2(-16))

  t = (-32 ± √(1024-64h))/-32

  t = 1 ± √(1 -h/16)

For h = 10 ft, the times are ...

  t = 1 ± √(3/8) ≈ {0.388, 1.612} . . . . seconds

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Using the quadratic formula is not the only way to solve a quadratic. One of my favorite methods is using a graphing calculator.

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