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Daphne has a preloaded games card that she is using to play games at the arcade as shown in the table.
How much did Daphne start with on her card?
by what amount does her card value change per game?
write an equation to represent the situation.


Daphne Has A Preloaded Games Card That She Is Using To Play Games At The Arcade As Shown In The Table How Much Did Daphne Start With On Her Card By What Amount class=

Sagot :

(a) Daphne starts with $25.00 on her card

(b) The amount by which her card value changes per game is -($0.5)

(c) y = 25 - 0.5·x

From the table of values, the amount

The table of values is presented as follows;

[tex]\begin{array}{ccc}&\ \ Games \ Played#&Amount \ on \ Card \ (\$)\\Start&0&25\\&3&23.5\\&6&22\\&9&20.50\end{array}[/tex]

(a) From the table above, when the number of game played = 0, the amount on the card = 25

Therefore;

The amount that Daphne start with on her card = $25

(b) The amount her card changes per game is given by the rate of change as follows;

[tex]Rate \ of \ change = \dfrac{dy}{dx}[/tex]

Therefore;

[tex]Rate \ of \ change = \dfrac{y_2 - y_1}{x_2 - x_1}[/tex]

Which gives;[tex]Rate \ of \ change = \dfrac{Present \ amount \ on \ card - Previous \ amount \ on \ card}{Present \ number of games played - Previous\ number of games played}[/tex]Taking any two points, we get;

Rate of change = (23.5 - 25)/(3 - 0) = -0.5

Therefore, her card value is drops by 0.5 per game

The amount by which her card value changes per game = -($0.5)

(c) We note that the rate of change of the Amount on Card, y, to the

number of Games Played, x, is constant, therefore, the relationship

between the variables is a straight line relationship, of the form, y = m·x + c, and we have;

m = The rate of change = -0.5

c = The y-intercept = The starting Amount on Card ($) = 25

Therefore, the equation is;

y = -0.5·x + 25 = 25 - 0.5·x

The required equation is, y = 25 - 0.5·x

Where;

y = The Amount on Card

x = The number of Games Played

Learn more about straight line equations here;

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