The appropriate answer will be "Molarity of 2 mol/L and osmolarity of 8 osmol/L".
The given values are:
Number of moles,
= 2 moles
Volume of solution,
= 1 L
Now,
→ The molarity of solution will be:
= [tex]\frac{Number \ of \ moles}{Volume \ of \ solution}[/tex]
= [tex]\frac{2}{1}[/tex]
= [tex]2 \ mol/L[/tex]
and,
→ The osmolarity of the solution will be:
= [tex]Molarity\times n[/tex]
According to the question [tex]feCl_3=1fe+3Cl[/tex], then n = 4.
= [tex]2\times 4[/tex]
= [tex]8 \ osmol/L[/tex]
Thus the above answer is correct.
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