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write out the products that would be created during this neutralization reaction H2SO4 + Cu(OH)2​

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Answer:

H2SO4+CU(OH)2 = CUSO4+2H2O

The general neutralization reaction between an acid and a base takes the form: acid + base → salt + water.

If you have some acid HA neutralizing some base BOH, the salt would be an ionic compound composed of the conjugate acid of BOH (i.e., B⁺) and the conjugate base of HA (i.e., A⁻).

Applied here, H2SO4 and Cu(OH)2 would react to form a salt CuSO4 (the Cu²⁺ ions coming from the copper(II) hydroxide and the SO4²⁻ ions coming from the sulfuric acid) and H2O.

Thus, the products of this neutralization reaction would be copper(II) sulfate (CuSO₄) and water (H₂O).

The balanced equation for this reaction would accordingly be:

H₂SO₄ + Cu(OH)₂ → CuSO₄ + 2H₂O.

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