Hoda2077idn
Answered

Discover a world of knowledge and community-driven answers at IDNLearn.com today. Our experts provide timely, comprehensive responses to ensure you have the information you need.

write out the products that would be created during this neutralization reaction H2SO4 + Cu(OH)2​

Sagot :

Vinaychoudaryidn

Answer:

H2SO4+CU(OH)2 = CUSO4+2H2O

The general neutralization reaction between an acid and a base takes the form: acid + base → salt + water.

If you have some acid HA neutralizing some base BOH, the salt would be an ionic compound composed of the conjugate acid of BOH (i.e., B⁺) and the conjugate base of HA (i.e., A⁻).

Applied here, H2SO4 and Cu(OH)2 would react to form a salt CuSO4 (the Cu²⁺ ions coming from the copper(II) hydroxide and the SO4²⁻ ions coming from the sulfuric acid) and H2O.

Thus, the products of this neutralization reaction would be copper(II) sulfate (CuSO₄) and water (H₂O).

The balanced equation for this reaction would accordingly be:

H₂SO₄ + Cu(OH)₂ → CuSO₄ + 2H₂O.

Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. Your questions deserve accurate answers. Thank you for visiting IDNLearn.com, and see you again for more solutions.