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Calculate the molarity of 29.25 grams of NaCI in 2.0 liters of solution

Sagot :

Drpelezoidn

Answer:

[NaCl(aq)] = 0.25M

Explanation:

Molarity = moles solute / volume of solution in liters

moles NaCl in 29.25 grams = 29.25g/58g·mol⁻¹ = 0.5043 mole

Molarity = 0.5043 mole NaCl / 2 Liters = 0.2555M ≅ 0.25M (2 sig-figs)

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