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Sagot :
Point slope form equation: y-y1=m(x-x1)
Step 1: plug in the x and y values- y-9=m(x-8)
Step 2: plug in the slope, then you have your answer- y-9=3(x-8)
Step 1: plug in the x and y values- y-9=m(x-8)
Step 2: plug in the slope, then you have your answer- y-9=3(x-8)
The equation of a line passing through the point (8, 9) with a slope of 3 is y = 3x - 15.
What is the equation of a line passing through two given points in 2-dimensional plane?
Suppose the given points are [tex](x_1, y_1) and (x_2, y_2),[/tex]
then the equation of the straight line joining both two points is given by
[tex](y - y_1) = \dfrac{y_2 - y_1}{x_2 - x_1} (x -x_1)[/tex]
We have been given a line passing through the point (8, 9) with a slope of 3.
then the equation of the straight line joining both two points is given by
[tex](y - y_1) = \dfrac{y_2 - y_1}{x_2 - x_1} (x -x_1)[/tex]
Its slope would be:
[tex]m = \dfrac{y_2-y_1}{x_2-x_1}[/tex]
m = 3
Therefore, the equation of the straight line
[tex](y - 9) = 3 (x -8)\\\\y - 9 = 3x - 24\\\\y = 3x -15[/tex]
Hence, the equation of a line passing through the point (8, 9) with a slope of 3 is y = 3x - 15.
Learn more about straight-line equations here:
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