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Answer:
0.0313 mole.
Explanation:
From the question given above, the following data were obtained:
Volume of solution = 125 mL
Molarity of NaNO₃ = 0.25 M
Number of mole of NaNO₃ =?
Next, we shall convert 125 mL to litre (L). This can be obtained as follow:
1000 mL = 1 L
Therefore,
125 mL = 125 mL × 1 L / 1000 mL
125 mL = 0.125 L
Thus, 125 mL is equivalent to 0.125 L.
Finally, we shall determine the number of mole of NaNO₃ in the solution. This can be obtained as follow:
Volume of solution = 0.125 L.
Molarity of NaNO₃ = 0.25 M
Number of mole of NaNO₃ =?
Molarity = mole / Volume
0.25 = mole of NaNO₃ / 0.125
Cross multiply
Mole of NaNO₃ = 0.25 × 0.125
Mole of NaNO₃ = 0.0313 mole.