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Find the distance between P and Q. P(-3, -4), Q(6, -7)

Sagot :

Saurabhbhoir456idn

Answer:

Please find attached pdf

Step-by-step explanation:

Raj1036idn

Step-by-step explanation:

P=(-3,-4)=(X1,Y1)

Q=(6,-7)=(X2,Y2)

Pq=root under( x2-x1)^2+(y2-y1)^2

= root under {6-(-3)}^2+{-7-(-4)}^2

= {6+3}^2+{-7+4}^2

= 9^2+(-3)^2

= 81+9

= 90

= 3root under10 unit.#

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