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(Help please) Find both the perimeter and the area of the following rectangle
2x+3
X+6
Perimeter:_____
Area:____

Help Please Find Both The Perimeter And The Area Of The Following Rectangle 2x3 X6 Perimeter Area class=

Sagot :

Given:

Length of a rectangle = (2x+3) units

Width of the rectangle = (x+6) units

To find:

The perimeter and the area of the rectangle.

Solution:

We know that, the perimeter of the rectangle is

[tex]Perimeter=2(Length+Width)[/tex]

[tex]Perimeter=2((2x+3)+(x+6))[/tex]

[tex]Perimeter=2(3x+9)[/tex]

[tex]Perimeter=6x+18[/tex]

The area of rectangle is

[tex]Area=Length\times width[/tex]

[tex]Area=(2x+3)\times (x+6)[/tex]

[tex]Area=2x^2+12x+3x+18[/tex]

[tex]Area=2x^2+15x+18[/tex]

Therefore, [tex]Perimeter=6x+18[/tex] and [tex]Area=2x^2+15x+18[/tex].

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