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Sagot :
Complete question is;
A 50.-ohm resistor, an unknown resistor R, a 120-volt source, and an ammeter are connected in a complete circuit. The ammeter reads 0.50 ampere.
A) Calculate the equivalent resistance of the circuit shown.
B) Determine the resistance of resistor R shown in the diagram.
Answer:
A) R_eq = 240 Ω
B) R = 190 Ω
Explanation:
A) To get the equivalent resistance, we will use the formula;
R = V/I
Where;
V is Voltage
I is current
R is equivalent resistance
From the question, V = 120 V and I = 0.5A
Thus;
R_eq = 120/0.5
R_eq = 240 Ω
B) From the image, we see that the resistors are connected in series.
Formula for resistors in series is;
R = R1 + R2 +..... Rn
Thus;
240 = 50 + R
R = 240 - 50
R = 190 Ω
A) The equivalent resistance of the circuit shown will be 240 Ω.
B) The resistance of resistor R will be 190 Ω
What is resistance?
Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.
The given data in the problem is;
R is the resistance = 50.-ohm
v is the voltage = 120-volt source
I is the value of the current =0.50 ampere.
A) The equivalent resistance of the circuit shown will be 240 Ω.
According to ohm's law
[tex]\rm R= \frac{V}{I} \\\\ \rm R= \frac{120}{0.5} \\\\ \rm R=240 \ ohm[/tex]
Hence the equivalent resistance of the circuit shown will be 240 Ω.
B) The resistance of resistor R will be 190 Ω
The given resistors are connected in the series;
R = R1 + R2 +..... Rn
240 = 50 + R
R = 240 - 50
R = 190 Ω
Hence the resistance of resistor R will be 190 Ω
To learn more about the resistance refer to the link;
https://brainly.com/question/20708652
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