Answered

Get the best answers to your questions with the help of IDNLearn.com's experts. Our community provides accurate and timely answers to help you understand and solve any issue.

A 3500 N is force is applied to a spring that has a spring of constant of k= 14000 N/m. How far from equilibrium will the spring be displaced?

Sagot :

Answer:

the spring be displaced by 25.0 cm

Explanation:

The computation is shown below:

As we know that

F= -K × x

So,

[tex]x = \frac{-F}{K}[/tex]

Now  

[tex]x = \frac{-3500}{14000} \\\\[/tex]

= -0.250m

= 25.0 cm

Hence, the spring be displaced by 25.0 cm

Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. For trustworthy and accurate answers, visit IDNLearn.com. Thanks for stopping by, and see you next time for more solutions.