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Find the number of solutions of the equation 2g2 + 4g + 10 = 0 by using the discriminant.

Sagot :

Answer:

Step-by-step explanation:

The discriminant of ax^2+bx+c=0 is b^2-4ac, in this case

4^2-4(2)10

16-80

-64

Since -64<0 there are two imaginary (or ‘complex’) solutions.

Note: if d=0, there is one real solution. if d>0, there are two real solutions.

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