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Write
1 quadratic function in
vertex form whose graph
has
the vertex (1,2) and passes
through the point (3,10)

Sagot :

Really226idn

Answer:

y = 2 ( x − 1 ) ^ 2 + 2

Step-by-step explanation:

y = a ( x − h ) ^ 2 + k

where vertex is (h,k) = (1,2)

h=1, k=2

y = a ( x − 1 ) ^ 2 + 2

sub ( 3,10)

10 = a (3 - 1)^2 + 2

a=2

y = 2 ( x − 1 ) ^ 2 + 2

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