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A light bulb has a resistance of 4 ohms and a current of 2 A. What is the voltage across the bulb?
volts

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Answer:

8 V

Explanation:

V= IR

V = 4×2

V= 8 V

The answer is the ohms × current

Voltage is an electrical difference of potential across the circuit. The voltage of the bulb is 8V with a current of 2 A and a resistance of 4 ohms.

What is ohms law?

Ohms law gives the relation between the current (I) in Amperes, voltage (V) in volts, and resistance (R) in ohms. The formula to calculate voltage is given as,

[tex]\rm V = I \times R[/tex]

Given,

Current (I) = 2 Ampere

Resistance (R) = 4 ohms

Substituting values in the equation to calculate voltage as:

[tex]\begin{aligned} \rm V &= \rm I \times R\\\\&= 2 \times 4 \\\\&= 8\end{aligned}[/tex]

Therefore, 8 V is the voltage developed across the bulb with 4-ohm resistance.

Learn more about voltage here:

https://brainly.com/question/15263092

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