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Given the system of equations, what is the value of the system determinant?
2x + y = 8
x - y = 10
0-1
0-2
0-3


Sagot :

Given:

The system of equation is

[tex]2x+y=8[/tex]

[tex]x-y=10[/tex]

To find:

The value of the system determinant.

Solution:

If two equations of a system of equations are [tex]a_1x+b_1y=c_1[/tex] and [tex]a_2x+b_2y=c_2[/tex], then the system determinant is

[tex]D=\left|\begin{matrix}a_1&b_1\\a_2&b_2\end{matrix}\right|[/tex]

[tex]D=a_1b_2-b_1a_2[/tex]

The given two equations are [tex]2x+y=8[/tex] and [tex]x-y=10[/tex].

Here, [tex]a_1=2,b_1=1,c_1=8, a_2=1,b_2=-1,c_2=10[/tex].

[tex]D=\left|\begin{matrix}2&1\\1&-1\end{matrix}\right|[/tex]

[tex]D=(2)(-1)-(1)(1)[/tex]

[tex]D=-2-1[/tex]

[tex]D=-3[/tex]

The value of the system determinant is -3. Therefore, the correct option is C.

Answer:

-3

Step-by-step explanation:

2x+-3=8

x-3=10