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Find an equation of the line parallel to y = 3x + 2 and that passes through the point (-1, -3)
In order to be parallel to a line, two lines must have the same slope. The slope of y=3x+2 is 3. So the slope of the other equation has the be 3. y=3x+b. Now we can plug in the x and y values given by the point to calculate the b in the equation. -3=3(-1)+b -3=-3+b b=0 So the equation is y=3x
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