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Sagot :
Answer:
Options (1), (3) and (4)
Step-by-step explanation:
From ΔABC given in the picture,
By Pythagoras theorem
Hypotenuse² = (Leg 1)² + (Leg 2)²
BC² = AB² + AC²
(18)² = 9² + AC²
AC = [tex]\sqrt{324-81}[/tex]
AC = [tex]9\sqrt{3}[/tex] cm
sin(C) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]
= [tex]\frac{AB}{BC}[/tex]
= [tex]\frac{9\sqrt{3}}{18}[/tex]
sin(C) = [tex]\frac{\sqrt{3} }{2}[/tex]
sin(B) = [tex]\frac{AC}{BC}[/tex]
= [tex]\frac{9}{18}[/tex]
= [tex]\frac{1}{2}[/tex]
cos(B) = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]
= [tex]\frac{9\sqrt{3}}{18}[/tex]
= [tex]\frac{\sqrt{3} }{2}[/tex]
tan(B) = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}[/tex]
= [tex]\frac{AC}{AB}[/tex]
= [tex]\frac{9}{9\sqrt{3} }[/tex]
= [tex]\frac{1}{\sqrt{3} }[/tex]
tan(C) = [tex]\frac{AB}{AC}[/tex]
= [tex]\frac{9\sqrt{3}}{9}[/tex]
= [tex]\sqrt{3}[/tex]
Therefore, Options (1), (3) and (4) are the correct options.
Answer:
Options (1), (3) and (4)
Step-by-step explanation:
From ΔABC given in the picture,
By Pythagoras theorem
Hypotenuse² = (Leg 1)² + (Leg 2)²
BC² = AB² + AC²
(18)² = 9² + AC²
AC =
AC = cm
sin(C) =
=
=
sin(C) =
sin(B) =
=
=
cos(B) =
=
=
tan(B) =
=
=
=
tan(C) =
=
=
Therefore, Options (1), (3) and (4) are the correct options.Step-by-step explanation:
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