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write the standard form of the quadratic function that has the indicated vertex and whose graph passes through the given point. y=a(x-h)^2+k
vertex:(4,-1) point:(2,3)

Sagot :

Really226idn

Answer:

y =  ( x − 2 ) ^ 2 + 3

y =   x^2 − 4x + 7

Step-by-step explanation:

y = a ( x − h ) ^ 2 + k

where vertex is (h,k) = (4,-1)

h=4, k=-1

y = a ( x − 4 ) ^ 2 - 1

sub ( 2,3 )

3 = a (2 - 4)^2 - 1

a=1

y = 1 ( x − 2 ) ^ 2 + 3

y =  ( x^2 − 4x + 4 )  + 3

y =   x^2 − 4x + 7

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