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Sagot :
Answer:
Here are #1 threw #3 answers
#1 is 10
# 2 is
6 + 7 + 8 + 9 + 10 + 10 + 10 + 12 + 14 + 14 = 100/10. The (Mean) = 10
(6- 10) + (7- 10) + (8- 10) + (9- 10) + (10- 10) + (10- 10) + (10- 10) + (12- 10) + (14- 10)
4 + 3 + 2 + 1 + 0 + 0 + 0 + 2 + 4
= 16/10 = 1 6/10
The (MAD) = 1 6/10
#3 Groups A & B
#4 sorry I can’t figure this out but I did 1/2/3
Step-by-step explanation:
Answer:
1. the company C used 10 drivers2. 6 + 7 + 8 + 9 + 10 + 10 + 10 + 12 + 14 + 14 = 100/10. The Mean = 10 (6- 10) + (7- 10) + (8- 10) + (9- 10) + (10- 10) + (10- 10) + (10- 10) + (12- 10) + (14- 10)4 + 3 + 2 + 1 + 0 + 0 + 0 + 2 + 4 = 16/10 = 1 6/103. The groups that had the most deliveries where group A and B4. So if there are 6 deliveries of group A and 14 deliveries from group B i think the MAD would be 4
Step-by-step explanation:
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