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if a 5.0 L balloon at 25 C were gently heated to 30 C, what would be the new volume?

Sagot :

Histrionicusidn

Answer:

The correct answer is - 5.08 L.

Explanation:

According to the Charles law, states that if the pressure and amount are constant, the volume of a gas is directly proportional to the Kelvin temperature,

V2=  [tex]\frac{V1T2} {T1}[/tex]

Converting value to kelvin:

25+273K=298K

30+273K=303K

Then V2= 5*303/298

V2  = 5.08 L

Cricetusidn

The new volume will be "5.08 L".

Given:

Volume,

  • [tex]V_1 = 5.0 \ L[/tex]

Temperature,

  • [tex]T_1 = 25^{\circ} C, or \ 298 \ K[/tex]
  • [tex]T_2 = 30^{\circ} C, or \ 303 \ K[/tex]

By using the Charles Law,

→ [tex]V_2 = \frac{V_1 T_2}{T_1}[/tex]

By substituting the values,

       [tex]= \frac{5\times 303}{298}[/tex]

       [tex]= 5.08 \ L[/tex]

Thus the response above is correct.

Learn more about volume here:

https://brainly.com/question/23093133

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