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What is an equation of the line that passes through the point (-3,-1) and is
perpendicular to the line x - 2y = 62

What Is An Equation Of The Line That Passes Through The Point 31 And Is Perpendicular To The Line X 2y 62 class=

Sagot :

Devishri1977idn

Answer:

y = -2x - 7

Step-by-step explanation:

x - 2y = 6

   -2y = -x + 6

Divide the whole equation by (-2)

[tex]\frac{-2y}{-2}=\frac{-x}{-2}+\frac{6}{-2}\\\\y = \frac{1}{2}x - 3[/tex]

slope = 1/2

Slope of the line perpendicular to this line = -1/m = -1 ÷ (1/2)

                                                                      [tex]=(-1)*\frac{2}{1}\\\\= -2[/tex]

(-3, - 1)

y -y1 = m(x -x1)

y - [-1] = -2(x - [-3])

y + 1 = -2(x + 3)

y + 1= x* (-2)  + 3*(-2)

y + 1 = -2x - 6

    y = -2x - 6 - 1

     y = -2x - 7

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