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Examine the genotype for an individual who is AaBbCcDd. Predict the outcomes of meiosis and the potential gamete combinations
that could form from this individual. Select ALL that apply.
A)
50% of the gametes will be AaBbCcDd.
B)
1/16 of the gametes produced will be ABcd.
The individual could make gametes that contain ABCD.
D)
The individual could make gametes abcd half of the time.
E)
Only dominant traits will be present in the gametes from a heterozygous
individual

Sagot :

Fieryboi77idn

Answer: B,C

Explanation:

I did just did the USA test prep

Histrionicusidn

The outcomes of meiosis and the potential gamete combinations  that could form from the genotype for an individual who is AaBbCcDd:

  • B) 1/16 of the gametes produced will be ABcd.
  • C) The individual could make gametes that contain ABCD.

A gamete that is formed by the meiosis, is a reproductive cell which has haploid set of chromosomes arise from the genotype, the total number of chromosome in mature organism cells.

A a simple method to calculate the number of gametes:

  • Count the number of heterozygous alleles i.e Aa Bb Cc and Dd which means 4.

           n = 4

  • Then, total number of gametes will be  = [tex]2^{n}[/tex] or [tex]2^{4}[/tex] = 16

                  Thus 16 in this condition

The 16 types of gametes are formed by this individual by permutation and combination are:

ABCD,  AbCD,  ABcD,  ABCd,

ABcd,   AbcD,   ABCd,   Abcd,

aBCD,   aBCd,   aBcd,   aBcD,

abCD,   abCd,   abcd,  abcD.

Thus, the correct answer is -

  • B) 1/16 of the gametes produced will be ABcd.
  • C) The individual could make gametes that contain ABCD.

Learn more about permutation and combination:

https://brainly.com/question/17512033  

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