From tech troubles to travel tips, IDNLearn.com has answers to all your questions. Our community is here to provide the comprehensive and accurate answers you need to make informed decisions.

8.0 Kg of water is heater from 20°C to 40°C. The specific heat capacity of water is 4200 J/Kg °C. What is the energy supplied to the water?

Sagot :

Answer:

672000 J.

Explanation:

From the question,

q = cm(t₂-t₁)............................ Equation 1

Where q = heat energy supplied to the water, c = specific heat capacity of water, m = mass of water, t₂ = final temperature, t₁ = Initial temperature.

Given: m = 8.0 kg, c = 4200 J/kg°C, t₂ = 40°C, t₁ = 20°C

Substitute these values into equation 1

q = 8×4200×(40-20)

q = 8×4200×20

q = 672000 J.

Hence the energy suplied to the water is 672000 J.