IDNLearn.com provides a platform for sharing and gaining valuable knowledge. Ask any question and receive accurate, in-depth responses from our dedicated team of experts.
Sagot :
Answer:
It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.
Step-by-step explanation:
Given - In 4 minutes, a conveyor belt moves 800 pounds of recyclable
aluminum from the delivery truck to a storage area. A smaller belt
moves the same quantity of cans the same distance in 6 minutes.
To find - If both belts are used, find how long it takes to move the cans
to the storage area.
Proof -
Given that,
Larger belt take 4 minutes to transfer the aluminium from delivery truck to storage area.
⇒ Time taken by Larger belt = 4 min/ shifting
Also,
Smaller belt take 6 minutes to transfer the aluminium from delivery truck to storage area.
⇒ Time taken by Smaller belt = 6 min/ shifting
Now,
As we know that Time is inversely proportional to time, so
Rate of Larger Belt = [tex]\frac{1}{4}[/tex] shifting/min
Rate of Smaller Belt = [tex]\frac{1}{6}[/tex] shifting/min
Now,
Let us assume that , if both belts used then,
Total time taken = x min/shifting
Then, Rate = [tex]\frac{1}{x}[/tex] shifting/min
Now,
[tex]\frac{1}{4}[/tex] + [tex]\frac{1}{6}[/tex] = [tex]\frac{1}{x}[/tex]
⇒[tex]\frac{6 + 4}{24} = \frac{1}{x}[/tex]
⇒[tex]\frac{10}{24} = \frac{1}{x}[/tex]
⇒10x = 24
⇒x = [tex]\frac{24}{10}[/tex] = 2.4 minutes
∴ we get
It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.
Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. IDNLearn.com is your go-to source for accurate answers. Thanks for stopping by, and come back for more helpful information.
