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How many atoms are in 1.4 moles of H3PO4?

8.4 X 10^23 atoms
8.9 X 10^23 atoms
8.4 X 10^23 grams
8.4 X 10^23 moles

Sagot :

Spaceidn

Answer:

8.4 × 10²³ atoms H₃PO₄

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

  • Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 1.4 moles H₃PO₄

[Solve] atoms H₃PO₄

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

  1. [DA] Set up:                                                                                                      [tex]\displaystyle 1.4 \ mol \ H_3PO_4(\frac{6.022 \cdot 10^{23} \ atoms \ H_3PO_4}{1 \ mol \ H_3PO_4})[/tex]
  2. [DA] Multiply [Cancel out units]:                                                                    [tex]\displaystyle 8.4308 \cdot 10^{23} \ atoms \ H_3PO_4[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

8.4308 × 10²³ atoms H₃PO₄ ≈ 8.4 × 10²³ atoms H₃PO₄

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