IDNLearn.com: Your reliable source for finding expert answers. Ask anything and receive prompt, well-informed answers from our community of experienced experts.
Sagot :
Answer:
F_net = 1.125 10⁻⁶ N
positive direction of the x axis
Explanation:
The electric force is given by Coulomb's law
F =[tex]k \frac{q_1q_2}{r_{12}^2}[/tex]
also used charge of equal sign repel each other.
We appease this information to our problems
the charge q₁ is positive and the charge q₃ is positive for which the force is repulsive; ; a charge q₂ is negative so the force is attractive.
If we apply that the forces are vectors
F_net = - F₁₃ + F₂₃
F_net = [tex]-k \frac{q_1q_3}{r_{13}^2} + k \frac{q_2q_3}{r_{23}^2}[/tex]
F_net = k q₃ ( [tex]- \frac{q_1}{r_{13}^2} + \frac{q_2}{r_{23}^2}[/tex] )
let's look for the distances
r₁₃ = 2-0 = 2 cm = 2 10⁻² m
r₂₃ = 4-0 = 4 cm = 4 10⁻² m
let's substitute
F_net = 9 10⁹ 5 10⁻⁹ ( [tex]- \frac{1 \ 10^{-9}}{2 \ 10^{-2}} + \frac{3 \ 10^{-9}}{4 \ 10^{-2}}[/tex])
F_net = 45 (- 0.5 10⁻⁷ + 0.75 10⁻⁷)
F_net = 1.125 10⁻⁶ N
the positive sign indicates that the outside has a positive direction of the x axis, that is, it is to the right
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Your search for solutions ends here at IDNLearn.com. Thank you for visiting, and come back soon for more helpful information.
