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What is the equation, in point-slope form, for the line with a slope 2/3 that passes through the point (-5,-8)

Sagot :

Answer:

y = 2/3 x - 14/3

[tex]y = \frac{2}{3} x - \frac{14}{3} [/tex]

Step-by-step explanation:

[tex]y = mx + b \\ m \: is \: slope \\ b \: is \: y \: intercept[/tex]

with point (-5,-8) & slope = 2/3 fill in and solve for b

-8 = (2/3) (-5) + b

-8 = (-10/3) + b

-14/3 = b