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Find the Area of the figure below, composed of a parallelogram and one semicircle. Rounded to the nearest tenths place​

Find The Area Of The Figure Below Composed Of A Parallelogram And One Semicircle Rounded To The Nearest Tenths Place class=

Sagot :

We have a parallelogram and a half of circle.

The area of parallelogram are: A=basis*height

The area of circle are: A=πr², where r is the radius (half of diameter).  Thus the half circle have Area equals to:

[tex]A=\frac{\pi r^{2} }{2}[/tex]

Approaching π to 3,14

parallelogram:

b=26

h=13

A=13*26

A=338

Half circle:

r=12

A=(3,14*12²)/2

A=226,08

Total Area of the figure are:

A=338+226,08

A=564,08

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