Answered

IDNLearn.com provides a user-friendly platform for finding answers to your questions. Ask your questions and receive prompt, detailed answers from our experienced and knowledgeable community members.

The size of a TV is determined by the length of the diagonal of the TV. A 42" TV means the length from one corner to the other is 42 inches. If the diagonal forms a 30 degree angle with the base of the TV, what are the height and width of the TV? *

Sagot :

Answer:

length = 5.38 feet

Step-by-step explanation:

All the eq. can be solved by Phythagoras's theorem

1) Diagonal is 70 inches, height is 42 inches so

70^2 = 42^2 + width^2

width ^2 = 3136, width = 56 inches

2) Base is 2 ft, length of ladder = hypotenuse = 10 ft

Height^2 = 10^2 -2^2 = 96

Height = 9.8 ft

3) Equilateral triangle has a side of 6

If you drop a vertical line from one corner of triangle to opposite side it bisects the side into equal parts. So the length of base is 3

The hypotenuse is 6

So height is sqrt (6*6 -3*3) = sqrt (27) = 3sqrt(3) = 5.2

4) Height = 12, width = 5

Diagonal^2 = 12*12 + 5*5 = 169

Diagonal = 13

5) Plant is 5 ft tall, distance from the ground is 2 ft

length ^2 = 5*5 + 2*2 = 29

length = 5.38 feet

We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your questions find answers at IDNLearn.com. Thanks for visiting, and come back for more accurate and reliable solutions.