Kylebell2007idn
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Rembaidn

Answer:

f(x) = -(x-3)^2 + 4

Step-by-step explanation:

(h; k) are the coordinates of the vertex.

On the graph are (3, 4), therefore we have:

f(x) = a(x-3)^2 + 4

We have the x- intercept (1,0) -> x=1; y=0.

Substitute them into the equation:

0 = a(1 - 3)^2 + 4

0 = a(-2)^2 + 4

4a + 4 = 0 | -4

4a = -4   |-4

a = -1

So, we have the answer:

f(x) = -(x-3)^2 + 4

Vgrooveidn
f(x) -(x-3)^2 + 4
Answer:
(1-x) (x-5)
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