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One supermarket sold 72 cases of Zing soap, but only one-third as many cases of Essence soap. If each case holds 156 bars of soap, how many bars were sold in all

Sagot :

The sold 14,976 in total 1/3 of 72 is 24+72=96
96*156 =^
Abidemiokinidn

There will be 1334 bars sold in all if each case holds 156 bars of soap.

From the question, we are told that one supermarket sold 72 cases of Zing soap, if there is only one-third as many cases of Essence soap, then;

Amount of cases of Essence soap = one-third of 72

Amount of cases of Essence soap = [tex]\frac{1}{3} \times 72[/tex]

Amount of cases of Essence soap = 24cases

If each case holds 156 bars of soap, then we can write:

1 case = 56 bars of soap

To get the total bars that were sold. we can write:

24cases = x

DIvide both expressions:

[tex]\frac{1}{24} = \frac{56}{x} \\cross \ multiply\\1 \times x=24 \times 56\\x=1334 bars[/tex]

This shows that 1334 bars were sold in all

Learn more here: https://brainly.com/question/13805442

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