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How many moles of PbNO3 are there in 4.5 g of PbNO3?

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Answer:

0.017 moles PbNO₃

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table
  • Moles

Stoichiometry

  • Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 4.5 g PbNO₃

[Solve] moles PbNO₃

Step 2: Identify Conversions

[PT] Molar Mass of Pb - 207.2 g/mol

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of PbNO₃ - 207.2 + 14.01 + 3(16.00) = 269.21 g/mol

Step 3: Convert

  1. [DA] Set up:                                                                                                     [tex]\displaystyle 4.5 \ g \ PbNO_3(\frac{1 \ mol \ PbNO_3}{269.21 \ g \ PbNO_3})[/tex]
  2. [DA] Multiply/Divide [Cancel out units]:                                                        [tex]\displaystyle 0.016716 \ moles \ PbNO_3[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

0.016716 moles PbNO₃ ≈ 0.017 moles PbNO₃

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