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Find the sum of the first 14 terms: 2 + 6 + 18 + 54 +

Sagot :

Step-by-step explanation:

First term (a) = 2

Common ratio (r) = 6 /2 = 3

Now

sum of first 14 terms (S14)

[tex] = \frac{a( {r}^{n} - 1) }{r \: - 1} \\ = \frac{2( {3}^{14} - 1) }{3 - 1} \\ = \frac{4782968}{2} \\ = 2391484[/tex]

Hope it will help :)❤

The pattern here is x3.
2+3+18+54+162+486+1458+4374+13122+39366+118098+354294+1062882+3188646=4782965
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