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The verticals of the triangle shape are A (-2, 4) , B (-2,3) , and C (-5,2). If ABC is reflected across the line y = -1 to produce the image of A'B'C', What's the coordinate of B' after a reflection across the line y=-1?
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Sagot :

Given:

The vertices of a triangle are A (-2, 4) , B (-2,3) , and C (-5,2).

Triangle ABC is reflected across the line y = -1 to produce the image of A'B'C'.

To find:

The coordinate of B' after a reflection across the line y=-1.

Solution:

If a figure is reflected across the line y=b, then

[tex](x,y)\to (x,-(y-b)+b)[/tex]

[tex](x,y)\to (x,-y+b+b)[/tex]

[tex](x,y)\to (x,2b-y)[/tex]

The given triangle ABC is reflected across the line y=-1. So, the rule of reflection is

[tex](x,y)\to (x,2(-1)-y)[/tex]

[tex](x,y)\to (x,-2-y)[/tex]

The coordinates of point B are (-2,3). So,

[tex]B(-2,3)\to B'(-2,-2-3)[/tex]

[tex]B(-2,3)\to B'(-2,-5)[/tex]

Therefore, the coordinates of point B' are (-2,-5).

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