Answered

Ask questions, share knowledge, and connect with a vibrant community on IDNLearn.com. Receive prompt and accurate responses to your questions from our community of knowledgeable professionals ready to assist you at any time.

Nitrogen gas reacts with hydrogen gas to produce ammonia according to the following equation.

N2(g)+3H2(g) → 2NH3(g)
What is the mole of ammonia produced from 7.23 x 10−4 moles of the hydrogen reactant, assuming there is sufficient nitrogen to react?


7.23 x 10−47.23 x 10−4

8.42 x 10−38.42 x 10−3

4.82 x 10−44.82 x 10−4

4.83 x 10−3

Sagot :

Howyoulikethatidn

Answer:

4.82 x 10^-4

Explanation:

7.23 x 10^-4 mol H2   l    2 mol NH3

------------------------------------------------------- =  

                                   l    3 mol H2

(7.23 x 10^-4) x 2   /  3 =

4.82 x 10^-4

Hope this helped! ;)

The mole of ammonia produced from 7.23 x 10⁻⁴ moles of the hydrogen reactant when there is sufficient nitrogen to react is 4.82×10⁻⁴.

What is moles?

Moles is a unit which is used to estimate the amount of any substance and it is represented as:
n = W/M , where

W = given mass

M = molar mass

Given chemical reaction is:
N₂(g) + 3H₂(g) → 2NH₃(g)

In the question it is given that sufficient moles of N₂ is present, so the formation of product depends on the moles of H₂. From the stoichiometry of the reaction, it is clear that:

3 moles of H₂ = produce 2 moles of NH₃

7.23×10⁻⁴ moles of H₂ = produce 2/3 × 7.23×10⁻⁴=4.82×10⁻⁴ moles of NH₃

Hence, option (C) is correct i.e. 4.82×10⁻⁴.

To know more about moles, visit the below link:
https://brainly.com/question/1464305

We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. IDNLearn.com is committed to providing accurate answers. Thanks for stopping by, and see you next time for more solutions.