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simplify 2i/-4 + 3i please

Sagot :

2i

−4

+3i

=

5

2

i

Step-by-step explanation:

i think it helps

Answer:

[tex]\frac{6}{25}[/tex] - [tex]\frac{8}{25}[/tex] i

Step-by-step explanation:

Assuming you mean

[tex]\frac{2i}{-4+3i}[/tex]

To simplify, rationalise the denominator

Multiply the numerator/ denominator by the conjugate of the denominator

The conjugate of - 4 + 3i is - 4 - 3i , then

= [tex]\frac{2i(-4-3i)}{(-4+3i)(-4-3i)}[/tex] ← expand numerator and denominator

= [tex]\frac{-8i-6i^2}{16-9i^2}[/tex] [ note that i² = - 1 ]

= [tex]\frac{-8i+6}{16+9}[/tex]

= [tex]\frac{6-8i}{25}[/tex]

= [tex]\frac{6}{25}[/tex] - [tex]\frac{8}{25}[/tex] i ← in standard form