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A hydraulic press consist of of two
cylinders of cross sectional areas
0.2m2 and 5m². The piston in the
smaller cylinder is pushed down
with a force of 100N through a
distance 0.2m. calculate
Links
(0)
The pressure transmitted
(ii)
The force exerted by the
piston in the larger cylinder. ​

Sagot :

Answer:

Explanation:

i )

area of small piston = 0.2 m²

Force = 100 N

pressure created on small piston

= 100 / .2 = 500 N/m²

According to Pascal's law , this pressure will be transmitted to larger cylinder .

area of larger cylinder = 5 m²

ii )

pressure = force / area

force in the large cylinder = pressure x area of large cylinder

= 500 x 5

= 2500 N .

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