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Three vectors A,B and C are such that A=B+C and their magnitudes are 5,4 and 3 respectively.find the angle between A and C​

Sagot :

Answer:

B = A - C

=> B² = A² + C² - 2AC.cos(A,C)

=>

[tex]cos(a.c) = \frac{a {}^{2} + c {}^{2} - b {}^{2} }{2ac} = \frac{5 {}^{2} +3 {}^{2} - 4 {}^{2} }{2.5.3} = \frac{3}{5} [/tex]

=> angle between A and C = 53.13⁰

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