Answered

Get clear, concise, and accurate answers to your questions on IDNLearn.com. Join our Q&A platform to access reliable and detailed answers from experts in various fields.

According to the reaction below, how many grams of KCl (potassium chloride) can be formed from 70.90 g of chlorine with excess potassium?

2K + Cl2 ---> 2 KCl

Sagot :

Keziakh004idn

Answer:

149.1 g KCl

Explanation:

2 K  +  Cl₂  ⇒  2 KCl

This is your chemical equation.  Use this equation to figure out the stoichiometry between Cl₂ and KCl.  According to the equation, for every 2 moles of KCl, you need 1 mole of Cl₂, making the ratio between KCl and Cl₂ 2/1.

First, convert grams of Cl₂ to moles of Cl₂.  The molar mass is 70.906 g/mol.

(70.90 g Cl₂)/(70.906 g/mol) = 0.9999 mol Cl₂

Convert moles of Cl₂ to moles of KCl using the stoichiometric relationship.

(0.9999 mol Cl₂) × (2 mol KCl/1 mol Cl₂) = 1.9998 mol KCl

Convert moles of KCl to grams of KCl.  The molar mass is 74.55 g/mol.

(1.998 mol KCl) × (74.55 g/mol KCl) = 149.1 g KCl

You will produce 149.1 g KCl.

We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. For precise answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.