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Answer:
140 L (3 sig-figs; includes the zero)*
Explanation:
PV = nRT => V = nRT/P
P = 0.800atm
V = ?
n = 5 moles
R =0.08206 L·atm/mol·K
T = -1°C = (-1 + 273)K = 272K
V = nRT/P = (5mol)(0.08206 L·atm/mol·K)(272K)/(0.800atm) = 139.5 L
*=> 140 Liters (3 sig-figs) => zero is a sig-fig b/c it was result of rounding 139.5 Liters to obtain 140 Liters.