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Find the base of a triangle whose altitude is 12 cm and area is 96 cm

Sagot :

Given:

Altitude of a triangle = 12 cm

Area of the triangle = 96 sq. cm

To find:

The base of the triangle.

Solution:

The area of a triangle is

[tex]Area=\dfrac{1}{2}\times base\times height[/tex]

Putting Area = 96 and height = 12, we get

[tex]96=\dfrac{1}{2}\times base\times 12[/tex]

[tex]96=6\times base[/tex]

Divide both sides by 6.

[tex]\dfrac{96}{6}=base[/tex]

[tex]16=base[/tex]

Therefore, the base of the triangle is 16 cm.

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