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Given:
Altitude of a triangle = 12 cm
Area of the triangle = 96 sq. cm
To find:
The base of the triangle.
Solution:
The area of a triangle is
[tex]Area=\dfrac{1}{2}\times base\times height[/tex]
Putting Area = 96 and height = 12, we get
[tex]96=\dfrac{1}{2}\times base\times 12[/tex]
[tex]96=6\times base[/tex]
Divide both sides by 6.
[tex]\dfrac{96}{6}=base[/tex]
[tex]16=base[/tex]
Therefore, the base of the triangle is 16 cm.