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write exponential function that goes through (0, 19) and (6, 1216)

Sagot :

Answer:

f(x)=19(2)^x

Standard form of exponential graph is f(x) = ab^x

Plugging in (0, 19), you get

19 = ab^0 -> 19 = a(1)

a=19

f(x)=19b^x

1216 = 19(b)^6

64=b^6

b=2

-> f(x) = 19(2)^x

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