Answered

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In the following figure, a table of mass 0.44 Kg is pushed against an inclined surface with a 15 inclination angle. Find the amount of the horizontal component of the Weight

Sagot :

Answer:

W = 1.11 N

Explanation:

Given that,

Mass of a table, m = 0.44 kg

It is pushed against an inclined surface with a 15 inclination angle.

We need to find the amount of the horizontal component of the weight. The horizontal component of weight is given by :

[tex]W=mg\sin\theta\\\\W=0.44\times 9.8\times \sin(15)\\\\W=1.11\ N[/tex]

So, the amount of the horizontal component of the weight is 1.11 N.

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