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22.7 degrees Celsius = 22.7 + 273 = 295.7 K
[tex]\frac{(12.2)(150.4)}{295.7}=\frac{(9.7)(101.3)}{T_{2}} \\ \\ \frac{295.7}{(12.2)(150.4)}=\frac{T_{2}}{(9.7)(101.3)} \\ \\ T_{2}=\frac{(295.7)(9.7)(101.3)}{(12.2)(150.4)} \approx \boxed{158.35 \text{ K}}[/tex]