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A sample of nitrogen gas has a temperature of 22.7oC when the volume of the container is 12.2L and it is under 150.4kPa of pressure. What temperature, in Kelvin, would the gas need to be in order to occupy a 9.7L container at 101.3kPa? Show all your work and round your answer to the hundredths place.

Sagot :

22.7 degrees Celsius = 22.7 + 273 = 295.7 K

[tex]\frac{(12.2)(150.4)}{295.7}=\frac{(9.7)(101.3)}{T_{2}} \\ \\ \frac{295.7}{(12.2)(150.4)}=\frac{T_{2}}{(9.7)(101.3)} \\ \\ T_{2}=\frac{(295.7)(9.7)(101.3)}{(12.2)(150.4)} \approx \boxed{158.35 \text{ K}}[/tex]

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