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Mrs. B. invested ¢30,000; part at 5%, and part at 8%. The total interest on the
investment was $2,100. How much did she invest at each rate?
(Use semicolon to separate multiple answers)

Sagot :

Dana2022idn

Answer:

Let p be the amount invested at 8%. Then the amount invested at 5% would be 30,000-p. So:

.08p+.05(30,000-p)=2100

.03p+1500=2100

.03p=600

p=20,000

$20,000 was invested at 8%; $10,000 was invested at 5%

Step-by-step explanation:

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$20,000 was invested at 8% and $10,000 was invested at 5%

What is Algebra?

Algebra is the study of graphic formulas, while logic is the interpretation among those signs.

Mrs. B. invested ¢30,000; part at 5%, and part at 8%.

The total interest on the investment was $2,100.

Let p be the amount invested at 8%.

Then the amount invested at 5% would be 30,000 – p.

Then the equation will be

0.08p + 0.05(30000 – p) = 2100

On simplifying, we have

(0.08 – 0.05)p + 1500 = 2100

                         0.03p = 600

                                 p = $20,000

$20,000 was invested at 8% and $10,000 was invested at 5%

More about the Algebra link is given below.

https://brainly.com/question/953809

#SPJ2

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