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Suppose f is a polynomial such that f(0) = 47, f(1) = 32, f(2) = -13, and f(3) = 16. What is the sum of the coefficients of f?


Sagot :

It’s 32, give the brainliest to the other person :b, anyways ...

Answer:

32

Step-by-step explanation:

The sum of the coefficients of any polynomial f(x) equals f(1), since letting x = 1 in any term cx^n gives us the coefficient c. That is, if

[tex]f(x) = a_nx^n + a_{n-1}x^{n-1} + \cdots + a_1x + a_0[/tex],

then

[tex]f(1) &= a_n\cdot 1^n + a_{n-1}\cdot1^{n-1} + \cdots + a_1\cdot 1 + a_0\\&=a_n+a_{n-1} + \cdots + a_1 + a_0.[/tex]  

So, the sum of the coefficients of f is f(1) = 32.