Leighaneavesidn
Answered

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How many moles of PbCl2 are produced
if 14 moles of AlCl3 are consumed?
3Pb(NO3)2 + 2AlCl3 + 3PbCl2 + 2A1(NO3)3

Sagot :

Kampadu049idn

Answer:21 moles of PbCl2 formed

Explanation: 3Pb(NO3)2(aq) + 2AlCl3(aq) --> 3PbCl2(s) + 2Al(NO3)3(aq)

14 moles AlCl3 x 3 moles PbCl2/2 moles AlCl3 =21 moles of PbCl2 formed

Eduard22slyidn

The number of moles of PbCl₂ produced when 14 moles of AlCl₃ are consumed in the reaction is 21 moles

Balanced equation

3Pb(NO₃)₂ + 2AlCl₃ —> 3PbCl₂ + 2Al(NO₃)₃

From the balanced equation above,

2 moles of AlCl₃ reacted to produce 3 moles of PbCl₂.

How to determine the mole of PbCl₂ produced

From the balanced equation above,

2 moles of AlCl₃ reacted to produce 3 moles of PbCl₂.

Therefore,

14 moles of AlCl₃ will react to produce = (14 × 3) / 2 = 21 moles of PbCl₂.

Thus, 21 moles of PbCl₂ were obtained from the reaction.

Learn more about stoichiometry:

https://brainly.com/question/14735801

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