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Work Shown:
3(m+2) + 4(6+m)
3m+6 + 24 + 4m
(3m+4m) + (6+24)
7m+30
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Explanation:
In the second step, I used the distribution rule a*(b+c) = a*b+a*c. We multiply the outer term by every term inside. So for instance 3(m+2) = 3*m+3*2 = 3m+6. A similar situation applies to 4(6+m) as well. Afterward, I grouped and combined like terms.
We can think of 3m+4m = 7m as saying "I have 3 maps and someone gave me 4 more maps, so that means I have 3+4 = 7 maps now". The m is a place holder for any number.