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Sagot :
The equation k = √3abc + a² - b² + c² - 5b is an algebraic expression
The value of k = √3abc + a² - b² + c² - 5b when a = -2, b = -2 and c = 3 is 25
How to solve the expression?
The equation of k is given as:
k = √3abc + a² - b² + c² - 5b
Where
a = -2, b = -2 and c = 3
Substitute a = -2, b = -2 and c = 3 in the equation of k
k = √(3 * -2 * -2 * 3) + (-2)² - (-2)² + 3² - 5*-2
Evaluate the root expression
k = 6 + (-2)² - (-2)² + 3² - 5*-2
Evaluate the exponents and the products
k = 6 + 4 - 4 + 9 + 10
Evaluate the sum and the difference
k = 25
Hence, the value of k = √3abc + a² - b² + c² - 5b when a = -2, b = -2 and c = 3 is 25
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