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Given that
K
=
√
3
a
b
c
1
+
a
2
−
b
2
+
c
2
−
5
b

If
a
=
−
2
,
b
=
−
2
and
c
=
3

evaluate
K ik

Sagot :

MrRoyalidn

The equation k = √3abc + a² - b² + c² - 5b is an algebraic expression

The value of k = √3abc + a² - b² + c² - 5b when a = -2, b = -2 and c = 3 is 25

How to solve the expression?

The equation of k is given as:

k = √3abc + a² - b² + c² - 5b

Where

a = -2, b = -2 and c = 3

Substitute a = -2, b = -2 and c = 3 in the equation of k

k = √(3 * -2 * -2 * 3) + (-2)² - (-2)² + 3² - 5*-2

Evaluate the root expression

k = 6 + (-2)² - (-2)² + 3² - 5*-2

Evaluate the exponents and the products

k = 6 + 4 - 4 + 9 + 10

Evaluate the sum and the difference

k = 25

Hence, the value of k = √3abc + a² - b² + c² - 5b when a = -2, b = -2 and c = 3 is 25

Read more about algebraic expressions at:

https://brainly.com/question/4344214

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