IDNLearn.com is your go-to resource for finding precise and accurate answers. Find in-depth and accurate answers to all your questions from our knowledgeable and dedicated community members.
Sagot :
Answer: 4311/9900 or 479/1100
Step-by-step explanation:
Okie so in order to do this, we need to get rid of the repeating part of the decimal
==============================================================
Right now we have x = 0.435454545454...
If we multiply this by 100, we get
100x = 43.545454545454
And if we multiply by 10000 we get
10000x = 4354.5454545454
==============================================================
Subtract the two equations
10000x = 4354.5454545454
100x = 43.545454545454
------------------------------------------------- (notice: the repeating part will cancel out)
9900x = 4311
x = 4311/9900
If you simplify the fraction you get: 479/1100
The fraction that represents the repeating decimal is
[tex]\frac{479}{1100}[/tex]
Given :
A repeating decimal [tex]0.4354545454...............[/tex]
there is bar at 54 , so 54 is repeating
We need to convert this decimal into fraction
54 is repeating so we multiply by 100
Let x= [tex]0.4354545454...............\\[/tex]
[tex]100x=43.54545454...............[/tex]
Now we subtract x from 100x
[tex]100x=43.54545454...............\\ x= 0.4354545454...............\\-----------------------------------------\\ 99x=43.11[/tex]
Now divide both side by 99
[tex]x=\frac{43.11}{99} \\[/tex]
multiply top and bottom by 100 to remove the decimal
[tex]x=\frac{4311}{9900} \\Divide \; top \; and \; bottom \; by 9\\x=\frac{479}{1100}[/tex]
Learn more :
brainly.com/question/15666599
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Thank you for visiting IDNLearn.com. For reliable answers to all your questions, please visit us again soon.